We Got A Problem #13: Deal or No Deal
June 14, 2013 1 Comment
This short game is played with ten playing cards: an ace, two, three, …, nine, and a joker. I shuffle the cards and lay them face down.
Your decision: grab as many cards as you want, still face down. When you’re ready, flip them all over at once and win: $1 multiplied by the sum of the card values.
Except the joker. If you flip over the joker, you win nothing. Good day.
So, how many cards should you take to maximize your expected return? What would change if all nine non-joker cards were aces? Eight aces and a ten?